MECH5750 DoE Midterm Exam
MECH5750 DoE Midterm Exam. Fall 2016, due Midnight Sunday October 16th. Name _________________
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Get Help Now!QUIZ C to be answered by student ID last digit 3 or 5. Part II
Please show background Calculations. Think of this problem as a combination of treatments and DoE
- For the experiment to Minimize the yield of popcorn = # of un-popped Kernels (2 factors and one interaction)
Brand Ratio Brand*Ratio Yield (un-popped Kernels)
Test Popcorn of Oil Interaction Replication
Number (1) (2) (12) 1 2 SY2 Avg. Sy (Sy)2 V
1 – – ___ 6 4 52 5 10 100 2
2 + – ___ 5 4 41 4.5 9 81 0.5
3 – + ___ 8 64 8 8 64
4 + + ____ 3 9 3 3 9
Total 166 5.13 30 254
- Fill in the blanks for the levels of the interaction, and calculate the correction Factor CF = _______
- Complete the anova treatment Table and determine Experiment significance
Please Show Calculations. Use Assignment 3 problem 3.6 as a guide for the ANOVA. Between = Regression and Within = Error
Effect | DoF | SS | MS | F ratio | Significant
95% |
Between | Yes or No | ||||
Within | |||||
Total |
- Calculate the main effects and their interaction. Make sure to use the average of each experiment line.
Calculate 1 = __________ 2 = ________ 12 = _______
- Calculate Pooled estimate of Variance _______ using two methods. Indicate methods (they should be equal).
Method 1 _________________ ; Method 2 __________________ (Hint see assignment 3.4.e solution)
- What levels (+ or -) would be best for lowest un-popped kernels (Yield) values? Hint: one answer is intuitive
With Interaction: Factor 1_____ factor 2 ______ Yield Value______
Without Interaction: Factor 1_____factor 2 ______ Yield Value______
- Based on CI (factors), which factors are significant: 1_______, 2________12__________
- Calculate the average, standard error (s/√n) and 95% confidence interval for the following:
Hint: several CI (+/-) are the same and one answer is intuitive.
- Total Experiment: Average ___5.13____+/- ________;
- Treatment 1 (Experiment Line 1) only (6, 4)
Experiment line 1 Average ___5.0____+/ ______ (when considering line 1 only and ignoring experiment)
Experiment line 1 Average ___5.0____+/ ________ (when considering total experiment)
- Treatment 3 (Experiment Line 3) only (8)
Experiment line 3 Average ___8.0____+/ ________ (when considering line 3 only and ignoring experiment)
Experiment line 3 Average ___8.0____+/ ________ (when considering total experiment
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